0 Can anyone explain why $1\ \mathrm {m}^3$ is $1000$ liters? I just don't get it. 1 cubic meter is $1\times 1\times1$ meter.

Understanding the Context

A cube. It has units $\mathrm {m}^3$. A liter is liquid amount measurement. 1 liter of milk, 1 liter of water, etc.

Key Insights

Does that mean if I pump $1000$ liters of water they would take exactly $1$ cubic meter of space? A hypothetical example: You have a 1/1000 chance of being hit by a bus when crossing the street. However, if you perform the action of crossing the street 1000 times, then your chance of being ... probability - 1/1000 chance of a reaction. If you do the action 1000 ...

Final Thoughts

For a quick back-of-the-envelope computation, you can note that $2^ {10}$ is only a little larger than $10^3$, so $2^ {1000} = (2^ {10})^ {100}$ is larger than $10^ {300}$, though not by much; so $2^ {1000}$ should have close to, but perhaps a few more, than 300 digits. 1 $3^ {1000}$ is hard to compute by hand because of the $1000$. Can you learn anything from trying smaller exponents instead? 1 the number of factor 2's between 1-1000 is more than 5's.so u must count the number of 5's that exist between 1-1000.can u continue? Question: Express the function $\frac {n^3} {1000} - 100n^2 - 100n + 3$ in terms of the Θ notation and prove that your expression in fact fits into the Θ definition. asymptotics - How to find $\frac {n^3} {1000} - 100n^2 - 100n + 3$ in ...

49 How to solve this problem, I can not figure it out: If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23. Find the sum of all the multiples of 3 or 5 below 1000. Find the sum of all the multiples of 3 or 5 below 1000 The last digit of $3^5$ is $3$ The last digit of $3^6$ is $9$ Notice a pattern?